**6.23**Bag of

**Cement**,

**12.48**bag of

**Sand**&

**25**bag of

**Aggregate**is required for 1m3 of m15 concrete, mix with proportion of 1:2:4 cement, sand, aggregate respectively, the whole calculation with concept mention below.

### Calculation for 1 m3 M15 grade concrete

In m15 concrete total proportion of materials is 7 (1 portion cement+2 portion sand +4 portion aggregate also known as stone chips).

So, in 1m3 concrete

Cement = 1/7 = 0.142 m3 is equals

Sand = 2/7 = 0.285 m3 is equals

Aggregate = 4/7 = 0.571 m3 is equals

**4.05 Bag**of cement (1 Bag of cement = 0.035 m3 in volume).Sand = 2/7 = 0.285 m3 is equals

**8.10 Bag**of sand (measure in same Cement bag of 0.035 m3).Aggregate = 4/7 = 0.571 m3 is equals

**16.20 Bag**of aggregate (measure in Cement bag of 0.035 m3).
The above calculation for

*dry volume***of concrete for 1 m3 M15 concrete.**
In practical we use

**wet concrete for casting, for this reason we have to consider the shrinkage of concrete because in combine with water dry concrete shrinks & reduced its volume with respect to the dry volume.**To get 1 m3 wet concrete we have to procure 1.54 m3 dry concrete.

Now to get the exact number of bags of cement, sand, aggregate for casting we have to multiply the dry volume (volume converted to bags) with multiplying factor

**1.54**which is nothing but the ratio of wet to dry volume of concrete also known as**shrinkage ratio**of concrete.- Cement = 4.05 * 1.54
**= 6.23**Bag of cement. - Sand = 8.10 * 1.54
**= 12.48**Bag - Aggregate = 16.20 * 1.54
**= 25**Bag

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